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13001310241 is a prime number
BaseRepresentation
bin11000001101111000…
…00100000000100001
31020120002020222202221
430012330010000201
5203111313411431
65550035111041
7640120212403
oct140674040041
936502228687
1013001310241
11557199a8a7
12262a142481
1312c27401aa
148b49cab73
15511610111
hex306f04021

13001310241 has 2 divisors, whose sum is σ = 13001310242. Its totient is φ = 13001310240.

The previous prime is 13001310229. The next prime is 13001310263. The reversal of 13001310241 is 14201310031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11728890000 + 1272420241 = 108300^2 + 35671^2 .

It is an emirp because it is prime and its reverse (14201310031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13001310241 - 29 = 13001309729 is a prime.

It is not a weakly prime, because it can be changed into another prime (13001310221) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500655120 + 6500655121.

It is an arithmetic number, because the mean of its divisors is an integer number (6500655121).

Almost surely, 213001310241 is an apocalyptic number.

It is an amenable number.

13001310241 is a deficient number, since it is larger than the sum of its proper divisors (1).

13001310241 is an equidigital number, since it uses as much as digits as its factorization.

13001310241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 13001310241 its reverse (14201310031), we get a palindrome (27202620272).

The spelling of 13001310241 in words is "thirteen billion, one million, three hundred ten thousand, two hundred forty-one".