Base | Representation |
---|---|
bin | 1011110100110001101010… |
… | …0010010111001001010011 |
3 | 1201000220122201210102101120 |
4 | 2331030122202113021103 |
5 | 3201003141133022212 |
6 | 43352415300333323 |
7 | 2511212416653204 |
oct | 275143242271123 |
9 | 51026581712346 |
10 | 13001311220307 |
11 | 4162909270a43 |
12 | 155b8a89a4243 |
13 | 734031521517 |
14 | 32d3a42275ab |
15 | 1782d984188c |
hex | bd31a897253 |
13001311220307 has 8 divisors (see below), whose sum is σ = 17372522409984. Its totient is φ = 8648820422088.
The previous prime is 13001311220299. The next prime is 13001311220353. The reversal of 13001311220307 is 70302211310031.
13001311220307 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13001311220307 - 23 = 13001311220299 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13001311220357) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4680096243 + ... + 4680099020.
It is an arithmetic number, because the mean of its divisors is an integer number (2171565301248).
Almost surely, 213001311220307 is an apocalyptic number.
13001311220307 is a deficient number, since it is larger than the sum of its proper divisors (4371211189677).
13001311220307 is an equidigital number, since it uses as much as digits as its factorization.
13001311220307 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9360195729.
The product of its (nonzero) digits is 756, while the sum is 24.
Adding to 13001311220307 its reverse (70302211310031), we get a palindrome (83303522530338).
The spelling of 13001311220307 in words is "thirteen trillion, one billion, three hundred eleven million, two hundred twenty thousand, three hundred seven".
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