Base | Representation |
---|---|
bin | 1011110100110001101010… |
… | …0010010111001001001011 |
3 | 1201000220122201210102101021 |
4 | 2331030122202113021023 |
5 | 3201003141133022144 |
6 | 43352415300333311 |
7 | 2511212416653163 |
oct | 275143242271113 |
9 | 51026581712337 |
10 | 13001311220299 |
11 | 4162909270a36 |
12 | 155b8a89a4237 |
13 | 73403152150c |
14 | 32d3a42275a3 |
15 | 1782d9841884 |
hex | bd31a89724b |
13001311220299 has 2 divisors, whose sum is σ = 13001311220300. Its totient is φ = 13001311220298.
The previous prime is 13001311220213. The next prime is 13001311220353. The reversal of 13001311220299 is 99202211310031.
13001311220299 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (99202211310031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13001311220299 - 221 = 13001309123147 is a prime.
It is not a weakly prime, because it can be changed into another prime (13001311290299) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500655610149 + 6500655610150.
It is an arithmetic number, because the mean of its divisors is an integer number (6500655610150).
Almost surely, 213001311220299 is an apocalyptic number.
13001311220299 is a deficient number, since it is larger than the sum of its proper divisors (1).
13001311220299 is an equidigital number, since it uses as much as digits as its factorization.
13001311220299 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5832, while the sum is 34.
The spelling of 13001311220299 in words is "thirteen trillion, one billion, three hundred eleven million, two hundred twenty thousand, two hundred ninety-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •