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13001311220299 is a prime number
BaseRepresentation
bin1011110100110001101010…
…0010010111001001001011
31201000220122201210102101021
42331030122202113021023
53201003141133022144
643352415300333311
72511212416653163
oct275143242271113
951026581712337
1013001311220299
114162909270a36
12155b8a89a4237
1373403152150c
1432d3a42275a3
151782d9841884
hexbd31a89724b

13001311220299 has 2 divisors, whose sum is σ = 13001311220300. Its totient is φ = 13001311220298.

The previous prime is 13001311220213. The next prime is 13001311220353. The reversal of 13001311220299 is 99202211310031.

13001311220299 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (99202211310031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13001311220299 - 221 = 13001309123147 is a prime.

It is not a weakly prime, because it can be changed into another prime (13001311290299) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500655610149 + 6500655610150.

It is an arithmetic number, because the mean of its divisors is an integer number (6500655610150).

Almost surely, 213001311220299 is an apocalyptic number.

13001311220299 is a deficient number, since it is larger than the sum of its proper divisors (1).

13001311220299 is an equidigital number, since it uses as much as digits as its factorization.

13001311220299 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5832, while the sum is 34.

The spelling of 13001311220299 in words is "thirteen trillion, one billion, three hundred eleven million, two hundred twenty thousand, two hundred ninety-nine".