Base | Representation |
---|---|
bin | 10010111010110101110… |
… | …111110110101110100101 |
3 | 11121021212101200101011120 |
4 | 102322311313312232211 |
5 | 132300132122112243 |
6 | 2433134440524153 |
7 | 162634316625066 |
oct | 22726567665645 |
9 | 4537771611146 |
10 | 1300131441573 |
11 | 461423339198 |
12 | 18bb83480659 |
13 | 957a93c9113 |
14 | 46cd8c0256d |
15 | 23c4573ac83 |
hex | 12eb5df6ba5 |
1300131441573 has 12 divisors (see below), whose sum is σ = 1742263620768. Its totient is φ = 862398666360.
The previous prime is 1300131441503. The next prime is 1300131441629. The reversal of 1300131441573 is 3751441310031.
It is not a de Polignac number, because 1300131441573 - 28 = 1300131441317 is a prime.
It is a super-2 number, since 2×13001314415732 (a number of 25 digits) contains 22 as substring.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1300131441503) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 5352993 + ... + 5590598.
It is an arithmetic number, because the mean of its divisors is an integer number (145188635064).
Almost surely, 21300131441573 is an apocalyptic number.
It is an amenable number.
1300131441573 is a deficient number, since it is larger than the sum of its proper divisors (442132179195).
1300131441573 is an equidigital number, since it uses as much as digits as its factorization.
1300131441573 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10943992 (or 10943793 counting only the distinct ones).
The product of its (nonzero) digits is 15120, while the sum is 33.
The spelling of 1300131441573 in words is "one trillion, three hundred billion, one hundred thirty-one million, four hundred forty-one thousand, five hundred seventy-three".
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