Base | Representation |
---|---|
bin | 111100100010101100… |
… | …0111000100111011011 |
3 | 110102120211201100122202 |
4 | 1321011120320213123 |
5 | 4112231332421024 |
6 | 135421025240415 |
7 | 12251563466156 |
oct | 1710530704733 |
9 | 412524640582 |
10 | 130013170139 |
11 | 50158055046 |
12 | 2124519310b |
13 | c34c836308 |
14 | 6415136c9d |
15 | 35ae0b5bae |
hex | 1e456389db |
130013170139 has 2 divisors, whose sum is σ = 130013170140. Its totient is φ = 130013170138.
The previous prime is 130013170031. The next prime is 130013170153. The reversal of 130013170139 is 931071310031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130013170139 - 28 = 130013169883 is a prime.
It is a super-2 number, since 2×1300131701392 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (130013170439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65006585069 + 65006585070.
It is an arithmetic number, because the mean of its divisors is an integer number (65006585070).
Almost surely, 2130013170139 is an apocalyptic number.
130013170139 is a deficient number, since it is larger than the sum of its proper divisors (1).
130013170139 is an equidigital number, since it uses as much as digits as its factorization.
130013170139 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1701, while the sum is 29.
The spelling of 130013170139 in words is "one hundred thirty billion, thirteen million, one hundred seventy thousand, one hundred thirty-nine".
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