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130014050452001 is a prime number
BaseRepresentation
bin11101100011111101000001…
…010010110000001000100001
3122001100012222201102012110222
4131203331001102300020201
5114020122233403431001
61140303344043532425
736246130241446412
oct3543750122601041
9561305881365428
10130014050452001
1138476716025831
12126b971652a115
13577137047a101
1424169dc249809
151006e6cd4561b
hex763f414b0221

130014050452001 has 2 divisors, whose sum is σ = 130014050452002. Its totient is φ = 130014050452000.

The previous prime is 130014050451959. The next prime is 130014050452067. The reversal of 130014050452001 is 100254050410031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 115778891203600 + 14235159248401 = 10760060^2 + 3772951^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130014050452001 is a prime.

It is a super-2 number, since 2×1300140504520012 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (130014050452301) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65007025226000 + 65007025226001.

It is an arithmetic number, because the mean of its divisors is an integer number (65007025226001).

Almost surely, 2130014050452001 is an apocalyptic number.

It is an amenable number.

130014050452001 is a deficient number, since it is larger than the sum of its proper divisors (1).

130014050452001 is an equidigital number, since it uses as much as digits as its factorization.

130014050452001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2400, while the sum is 26.

The spelling of 130014050452001 in words is "one hundred thirty trillion, fourteen billion, fifty million, four hundred fifty-two thousand, one".