Base | Representation |
---|---|
bin | 11000001101111000… |
… | …11100101000111011 |
3 | 1020120002110010011121 |
4 | 30012330130220323 |
5 | 203111330124011 |
6 | 5550041210111 |
7 | 640121112502 |
oct | 140674345073 |
9 | 36502403147 |
10 | 13001411131 |
11 | 5571a59685 |
12 | 262a190937 |
13 | 12c27770a7 |
14 | 8b4a15839 |
15 | 51162ee71 |
hex | 306f1ca3b |
13001411131 has 2 divisors, whose sum is σ = 13001411132. Its totient is φ = 13001411130.
The previous prime is 13001411077. The next prime is 13001411141. The reversal of 13001411131 is 13111410031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13001411131 - 217 = 13001280059 is a prime.
It is a super-2 number, since 2×130014111312 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13001411141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500705565 + 6500705566.
It is an arithmetic number, because the mean of its divisors is an integer number (6500705566).
Almost surely, 213001411131 is an apocalyptic number.
13001411131 is a deficient number, since it is larger than the sum of its proper divisors (1).
13001411131 is an equidigital number, since it uses as much as digits as its factorization.
13001411131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36, while the sum is 16.
Adding to 13001411131 its reverse (13111410031), we get a palindrome (26112821162).
The spelling of 13001411131 in words is "thirteen billion, one million, four hundred eleven thousand, one hundred thirty-one".
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