Base | Representation |
---|---|
bin | 111100100010101110… |
… | …0011110011011010011 |
3 | 110102120220111011212212 |
4 | 1321011130132123103 |
5 | 4112232103031233 |
6 | 135421101342335 |
7 | 12251604466406 |
oct | 1710534363323 |
9 | 412526434785 |
10 | 130014111443 |
11 | 50158638287 |
12 | 212455679ab |
13 | c34caa58b8 |
14 | 64152ddd3d |
15 | 35ae1eea48 |
hex | 1e4571e6d3 |
130014111443 has 2 divisors, whose sum is σ = 130014111444. Its totient is φ = 130014111442.
The previous prime is 130014111439. The next prime is 130014111533. The reversal of 130014111443 is 344111410031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 130014111443 - 22 = 130014111439 is a prime.
It is not a weakly prime, because it can be changed into another prime (130014161443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65007055721 + 65007055722.
It is an arithmetic number, because the mean of its divisors is an integer number (65007055722).
Almost surely, 2130014111443 is an apocalyptic number.
130014111443 is a deficient number, since it is larger than the sum of its proper divisors (1).
130014111443 is an equidigital number, since it uses as much as digits as its factorization.
130014111443 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 130014111443 its reverse (344111410031), we get a palindrome (474125521474).
The spelling of 130014111443 in words is "one hundred thirty billion, fourteen million, one hundred eleven thousand, four hundred forty-three".
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