Base | Representation |
---|---|
bin | 1011110100110010001001… |
… | …0110011001110101100110 |
3 | 1201000220222212110010111111 |
4 | 2331030202112121311212 |
5 | 3201003423212201314 |
6 | 43352440302055234 |
7 | 2511215601104362 |
oct | 275144226316546 |
9 | 51026885403444 |
10 | 13001442303334 |
11 | 4162976262621 |
12 | 155b92487a51a |
13 | 734052728c44 |
14 | 32d3b77ca2a2 |
15 | 1782e60d5ec4 |
hex | bd322599d66 |
13001442303334 has 8 divisors (see below), whose sum is σ = 19691504848080. Its totient is φ = 6437607353976.
The previous prime is 13001442303293. The next prime is 13001442303337. The reversal of 13001442303334 is 43330324410031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 13001442303296 and 13001442303305.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13001442303337) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31556898589 + ... + 31556899000.
It is an arithmetic number, because the mean of its divisors is an integer number (2461438106010).
Almost surely, 213001442303334 is an apocalyptic number.
13001442303334 is a deficient number, since it is larger than the sum of its proper divisors (6690062544746).
13001442303334 is a wasteful number, since it uses less digits than its factorization.
13001442303334 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 63113797694.
The product of its (nonzero) digits is 31104, while the sum is 31.
Adding to 13001442303334 its reverse (43330324410031), we get a palindrome (56331766713365).
The spelling of 13001442303334 in words is "thirteen trillion, one billion, four hundred forty-two million, three hundred three thousand, three hundred thirty-four".
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