13001450112 has 192 divisors, whose sum is σ = 45008683200. Its totient is φ = 3519148032.

The previous prime is 13001450107. The next prime is 13001450191. The reversal of 13001450112 is 21105410031.

It is a tau number, because it is divible by the number of its divisors (192).

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 110788 + ... + 195644.

It is an arithmetic number, because the mean of its divisors is an integer number (234420225).

Almost surely, 2^13001450112 is an apocalyptic number.

13001450112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13001450112, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (22504341600).

13001450112 is an abundant number, since it is smaller than the sum of its proper divisors (32007233088).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13001450112 is a wasteful number, since it uses less digits than its factorization.

13001450112 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 84903 (or 84888 counting only the distinct ones).

The product of its (nonzero) digits is 120, while the sum is 18.

Adding to 13001450112 its reverse (21105410031), we get a palindrome (34106860143).

The spelling of 13001450112 in words is "thirteen billion, one million, four hundred fifty thousand, one hundred twelve".