Base | Representation |
---|---|
bin | 111100100010110010… |
… | …1010010100110111111 |
3 | 110102121001211120211110 |
4 | 1321011211102212333 |
5 | 4112233201003320 |
6 | 135421223053103 |
7 | 12251633232612 |
oct | 1710545224677 |
9 | 412531746743 |
10 | 130016422335 |
11 | 50159976508 |
12 | 212462a1193 |
13 | c3504046a7 |
14 | 6415742179 |
15 | 35ae5095e0 |
hex | 1e459529bf |
130016422335 has 16 divisors (see below), whose sum is σ = 208192860000. Its totient is φ = 69286563840.
The previous prime is 130016422301. The next prime is 130016422337. The reversal of 130016422335 is 533224610031.
It is not a de Polignac number, because 130016422335 - 26 = 130016422271 is a prime.
It is a super-3 number, since 3×1300164223353 (a number of 34 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130016422337) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3451146 + ... + 3488615.
It is an arithmetic number, because the mean of its divisors is an integer number (13012053750).
Almost surely, 2130016422335 is an apocalyptic number.
130016422335 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
130016422335 is a deficient number, since it is larger than the sum of its proper divisors (78176437665).
130016422335 is a wasteful number, since it uses less digits than its factorization.
130016422335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6941018.
The product of its (nonzero) digits is 12960, while the sum is 30.
The spelling of 130016422335 in words is "one hundred thirty billion, sixteen million, four hundred twenty-two thousand, three hundred thirty-five".
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