Base | Representation |
---|---|
bin | 111100100010111001… |
… | …1000001000010110001 |
3 | 110102121022121101110011 |
4 | 1321011303001002301 |
5 | 4112240111123101 |
6 | 135421432134521 |
7 | 12252005636605 |
oct | 1710563010261 |
9 | 412538541404 |
10 | 130020020401 |
11 | 50160a03817 |
12 | 21247537441 |
13 | c35109431b |
14 | 6415ddb505 |
15 | 35ae9ba751 |
hex | 1e45cc10b1 |
130020020401 has 2 divisors, whose sum is σ = 130020020402. Its totient is φ = 130020020400.
The previous prime is 130020020359. The next prime is 130020020423. The reversal of 130020020401 is 104020020031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 111626151025 + 18393869376 = 334105^2 + 135624^2 .
It is a cyclic number.
It is not a de Polignac number, because 130020020401 - 229 = 129483149489 is a prime.
It is not a weakly prime, because it can be changed into another prime (130020120401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65010010200 + 65010010201.
It is an arithmetic number, because the mean of its divisors is an integer number (65010010201).
Almost surely, 2130020020401 is an apocalyptic number.
It is an amenable number.
130020020401 is a deficient number, since it is larger than the sum of its proper divisors (1).
130020020401 is an equidigital number, since it uses as much as digits as its factorization.
130020020401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 13.
Adding to 130020020401 its reverse (104020020031), we get a palindrome (234040040432).
The spelling of 130020020401 in words is "one hundred thirty billion, twenty million, twenty thousand, four hundred one".
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