Base | Representation |
---|---|
bin | 111100100010111001… |
… | …1010111001100111011 |
3 | 110102121022202222221201 |
4 | 1321011303113030323 |
5 | 4112240122024123 |
6 | 135421434115031 |
7 | 12252006465325 |
oct | 1710563271473 |
9 | 412538688851 |
10 | 130020111163 |
11 | 50160a65a28 |
12 | 2124757ba77 |
13 | c3510c6727 |
14 | 6416022615 |
15 | 35ae9d75ad |
hex | 1e45cd733b |
130020111163 has 2 divisors, whose sum is σ = 130020111164. Its totient is φ = 130020111162.
The previous prime is 130020111077. The next prime is 130020111173. The reversal of 130020111163 is 361111020031.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130020111163 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 130020111163.
It is not a weakly prime, because it can be changed into another prime (130020111173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65010055581 + 65010055582.
It is an arithmetic number, because the mean of its divisors is an integer number (65010055582).
Almost surely, 2130020111163 is an apocalyptic number.
130020111163 is a deficient number, since it is larger than the sum of its proper divisors (1).
130020111163 is an equidigital number, since it uses as much as digits as its factorization.
130020111163 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 19.
Adding to 130020111163 its reverse (361111020031), we get a palindrome (491131131194).
The spelling of 130020111163 in words is "one hundred thirty billion, twenty million, one hundred eleven thousand, one hundred sixty-three".
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