Base | Representation |
---|---|
bin | 11101100100000010101011… |
… | …001011111010000110011100 |
3 | 122001100210122212010022021220 |
4 | 131210002223023322012130 |
5 | 114020222202213310022 |
6 | 1140310230334253340 |
7 | 36246433555030623 |
oct | 3544025313720634 |
9 | 561323585108256 |
10 | 130020122010012 |
11 | 38479251291173 |
12 | 126ba92b957250 |
13 | 5771aca30b8a0 |
14 | 24170167646ba |
15 | 10071c5db585c |
hex | 7640ab2fa19c |
130020122010012 has 48 divisors (see below), whose sum is σ = 340922326617600. Its totient is φ = 38266791761088.
The previous prime is 130020122009963. The next prime is 130020122010017. The reversal of 130020122010012 is 210010221020031.
It is a junction number, because it is equal to n+sod(n) for n = 130020122009973 and 130020122010000.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130020122010017) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 18118742512 + ... + 18118749687.
It is an arithmetic number, because the mean of its divisors is an integer number (7102548471200).
Almost surely, 2130020122010012 is an apocalyptic number.
130020122010012 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
130020122010012 is an abundant number, since it is smaller than the sum of its proper divisors (210902204607588).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130020122010012 is a wasteful number, since it uses less digits than its factorization.
130020122010012 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 36237492242 (or 36237492240 counting only the distinct ones).
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 130020122010012 its reverse (210010221020031), we get a palindrome (340030343030043).
The spelling of 130020122010012 in words is "one hundred thirty trillion, twenty billion, one hundred twenty-two million, ten thousand, twelve".
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