Base | Representation |
---|---|
bin | 11000001101111101… |
… | …01111100111011011 |
3 | 1020120010120200222111 |
4 | 30012332233213123 |
5 | 203112003410042 |
6 | 5550102133151 |
7 | 640126200604 |
oct | 140676574733 |
9 | 36503520874 |
10 | 13002013147 |
11 | 557232aa12 |
12 | 262a4211b7 |
13 | 12c2928106 |
14 | 8b4b30dab |
15 | 5116ed517 |
hex | 306faf9db |
13002013147 has 2 divisors, whose sum is σ = 13002013148. Its totient is φ = 13002013146.
The previous prime is 13002013069. The next prime is 13002013217. The reversal of 13002013147 is 74131020031.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13002013147 is a prime.
It is not a weakly prime, because it can be changed into another prime (13002013547) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6501006573 + 6501006574.
It is an arithmetic number, because the mean of its divisors is an integer number (6501006574).
Almost surely, 213002013147 is an apocalyptic number.
13002013147 is a deficient number, since it is larger than the sum of its proper divisors (1).
13002013147 is an equidigital number, since it uses as much as digits as its factorization.
13002013147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 504, while the sum is 22.
Adding to 13002013147 its reverse (74131020031), we get a palindrome (87133033178).
The spelling of 13002013147 in words is "thirteen billion, two million, thirteen thousand, one hundred forty-seven".
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