Base | Representation |
---|---|
bin | 10010111010111010000… |
… | …010011011011001110110 |
3 | 11121022001021011200020022 |
4 | 102322322002123121312 |
5 | 132300303014301402 |
6 | 2433145414405142 |
7 | 162636125613314 |
oct | 22727202333166 |
9 | 4538037150208 |
10 | 1300201322102 |
11 | 4614598284a1 |
12 | 18bba29607b2 |
13 | 957baa25447 |
14 | 46d041d30b4 |
15 | 23c4b9412a2 |
hex | 12eba09b676 |
1300201322102 has 4 divisors (see below), whose sum is σ = 1950301983156. Its totient is φ = 650100661050.
The previous prime is 1300201322093. The next prime is 1300201322149. The reversal of 1300201322102 is 2012231020031.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 325050330524 + ... + 325050330527.
It is an arithmetic number, because the mean of its divisors is an integer number (487575495789).
Almost surely, 21300201322102 is an apocalyptic number.
1300201322102 is a deficient number, since it is larger than the sum of its proper divisors (650100661054).
1300201322102 is an equidigital number, since it uses as much as digits as its factorization.
1300201322102 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 650100661053.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 1300201322102 its reverse (2012231020031), we get a palindrome (3312432342133).
The spelling of 1300201322102 in words is "one trillion, three hundred billion, two hundred one million, three hundred twenty-two thousand, one hundred two".
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