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130020201300000 = 253551165360337
BaseRepresentation
bin11101100100000010101111…
…111010011000000000100000
3122001100210212101022122201010
4131210002233322120000200
5114020222333013100000
61140310242245540520
736246435540006024
oct3544025772300040
9561323771278633
10130020201300000
1138479292017990
12126ba952414740
135771b10880a3b
1424170230c4384
1510071ccd28d50
hex7640afe98020

130020201300000 has 576 divisors, whose sum is σ = 466103844194688. Its totient is φ = 31471257600000.

The previous prime is 130020201299983. The next prime is 130020201300103. The reversal of 130020201300000 is 3102020031.

It is a happy number.

130020201300000 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 2154869832 + ... + 2154930168.

It is an arithmetic number, because the mean of its divisors is an integer number (809208062838).

Almost surely, 2130020201300000 is an apocalyptic number.

130020201300000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 130020201300000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (233051922097344).

130020201300000 is an abundant number, since it is smaller than the sum of its proper divisors (336083642894688).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130020201300000 is an equidigital number, since it uses as much as digits as its factorization.

130020201300000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 61039 (or 61011 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 12.

Adding to 130020201300000 its reverse (3102020031), we get a palindrome (130023303320031).

The spelling of 130020201300000 in words is "one hundred thirty trillion, twenty billion, two hundred one million, three hundred thousand".