Base | Representation |
---|---|
bin | 11101100100000011000001… |
… | …110010111100010101100110 |
3 | 122001100211122021220100022211 |
4 | 131210003001302330111212 |
5 | 114020223441320412132 |
6 | 1140310332124514034 |
7 | 36246446142220510 |
oct | 3544030162742546 |
9 | 561324567810284 |
10 | 130020501341542 |
11 | 3847942641a5a9 |
12 | 126baa169ab91a |
13 | 5771b5aa94706 |
14 | 2417050ca8bb0 |
15 | 10071e9345147 |
hex | 7640c1cbc566 |
130020501341542 has 8 divisors (see below), whose sum is σ = 222892288014096. Its totient is φ = 55723072003512.
The previous prime is 130020501341539. The next prime is 130020501341567. The reversal of 130020501341542 is 245143105020031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-3 number, since 3×1300205013415423 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4643589333613 + ... + 4643589333640.
It is an arithmetic number, because the mean of its divisors is an integer number (27861536001762).
Almost surely, 2130020501341542 is an apocalyptic number.
130020501341542 is a deficient number, since it is larger than the sum of its proper divisors (92871786672554).
130020501341542 is an equidigital number, since it uses as much as digits as its factorization.
130020501341542 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9287178667262.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 130020501341542 its reverse (245143105020031), we get a palindrome (375163606361573).
The spelling of 130020501341542 in words is "one hundred thirty trillion, twenty billion, five hundred one million, three hundred forty-one thousand, five hundred forty-two".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •