Base | Representation |
---|---|
bin | 10010111010111010011… |
… | …001000001001101100011 |
3 | 11121022001200022112201201 |
4 | 102322322121001031203 |
5 | 132300311023303011 |
6 | 2433150145342031 |
7 | 162636230136565 |
oct | 22727231011543 |
9 | 4538050275651 |
10 | 1300207244131 |
11 | 461462102834 |
12 | 18bba4937917 |
13 | 957bc019ac3 |
14 | 46d04cd5335 |
15 | 23c4c210cc1 |
hex | 12eba641363 |
1300207244131 has 2 divisors, whose sum is σ = 1300207244132. Its totient is φ = 1300207244130.
The previous prime is 1300207244093. The next prime is 1300207244137. The reversal of 1300207244131 is 1314427020031.
It is a strong prime.
It is an emirp because it is prime and its reverse (1314427020031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1300207244131 - 211 = 1300207242083 is a prime.
It is a super-2 number, since 2×13002072441312 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1300207244131.
It is not a weakly prime, because it can be changed into another prime (1300207244137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650103622065 + 650103622066.
It is an arithmetic number, because the mean of its divisors is an integer number (650103622066).
Almost surely, 21300207244131 is an apocalyptic number.
1300207244131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1300207244131 is an equidigital number, since it uses as much as digits as its factorization.
1300207244131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4032, while the sum is 28.
The spelling of 1300207244131 in words is "one trillion, three hundred billion, two hundred seven million, two hundred forty-four thousand, one hundred thirty-one".
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