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13002100223112 = 233271113793596361
BaseRepresentation
bin1011110100110100100110…
…0100001010110010001000
31201000222200201102220202200
42331031021210022302020
53201011300124114422
643353025443400200
72511241110245010
oct275151144126210
951028621386680
1013002100223112
114163183680480
12155ba89083060
13734128b239a0
1432d43ad2cc40
15178333c452ac
hexbd34990ac88

13002100223112 has 768 divisors, whose sum is σ = 48019765248000. Its totient is φ = 3068869939200.

The previous prime is 13002100223059. The next prime is 13002100223141. The reversal of 13002100223112 is 21132200120031.

It is a super-2 number, since 2×130021002231122 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 2044030812 + ... + 2044037172.

It is an arithmetic number, because the mean of its divisors is an integer number (62525736000).

Almost surely, 213002100223112 is an apocalyptic number.

13002100223112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13002100223112, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (24009882624000).

13002100223112 is an abundant number, since it is smaller than the sum of its proper divisors (35017665024888).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13002100223112 is a wasteful number, since it uses less digits than its factorization.

13002100223112 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6842 (or 6835 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 13002100223112 its reverse (21132200120031), we get a palindrome (34134300343143).

The spelling of 13002100223112 in words is "thirteen trillion, two billion, one hundred million, two hundred twenty-three thousand, one hundred twelve".