Base | Representation |
---|---|
bin | 1011110100110100100110… |
… | …0100001010110010001001 |
3 | 1201000222200201102220202201 |
4 | 2331031021210022302021 |
5 | 3201011300124114423 |
6 | 43353025443400201 |
7 | 2511241110245011 |
oct | 275151144126211 |
9 | 51028621386681 |
10 | 13002100223113 |
11 | 4163183680481 |
12 | 155ba89083061 |
13 | 734128b239a1 |
14 | 32d43ad2cc41 |
15 | 178333c452ad |
hex | bd34990ac89 |
13002100223113 has 16 divisors (see below), whose sum is σ = 14083006408704. Its totient is φ = 11957171581440.
The previous prime is 13002100223059. The next prime is 13002100223141. The reversal of 13002100223113 is 31132200120031.
It is a cyclic number.
It is not a de Polignac number, because 13002100223113 - 217 = 13002100092041 is a prime.
It is a super-2 number, since 2×130021002231132 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13002100223183) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 12919428 + ... + 13889413.
It is an arithmetic number, because the mean of its divisors is an integer number (880187900544).
Almost surely, 213002100223113 is an apocalyptic number.
It is an amenable number.
13002100223113 is a deficient number, since it is larger than the sum of its proper divisors (1080906185591).
13002100223113 is a wasteful number, since it uses less digits than its factorization.
13002100223113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26809512.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 13002100223113 its reverse (31132200120031), we get a palindrome (44134300343144).
The spelling of 13002100223113 in words is "thirteen trillion, two billion, one hundred million, two hundred twenty-three thousand, one hundred thirteen".
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