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13002112313011 is a prime number
BaseRepresentation
bin1011110100110100101001…
…0010010010011010110011
31201000222201120012010222201
42331031022102102122303
53201011311223004021
643353030554444031
72511241315100353
oct275151222223263
951028646163881
1013002112313011
11416318a488828
12155ba91133617
1373412b497883
1432d43c798b63
15178334d32591
hexbd34a4926b3

13002112313011 has 2 divisors, whose sum is σ = 13002112313012. Its totient is φ = 13002112313010.

The previous prime is 13002112312997. The next prime is 13002112313087. The reversal of 13002112313011 is 11031321120031.

13002112313011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13002112313011 - 215 = 13002112280243 is a prime.

It is a super-2 number, since 2×130021123130112 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13002112313011.

It is not a weakly prime, because it can be changed into another prime (13002112313611) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6501056156505 + 6501056156506.

It is an arithmetic number, because the mean of its divisors is an integer number (6501056156506).

Almost surely, 213002112313011 is an apocalyptic number.

13002112313011 is a deficient number, since it is larger than the sum of its proper divisors (1).

13002112313011 is an equidigital number, since it uses as much as digits as its factorization.

13002112313011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 13002112313011 its reverse (11031321120031), we get a palindrome (24033433433042).

The spelling of 13002112313011 in words is "thirteen trillion, two billion, one hundred twelve million, three hundred thirteen thousand, eleven".