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13002119999969 is a prime number
BaseRepresentation
bin1011110100110100101010…
…1111100111000111100001
31201000222202002122200111212
42331031022233213013201
53201011320204444334
643353031431315505
72511241440324332
oct275151257470741
951028662580455
1013002119999969
114163193859091
12155ba9381bb95
1373412cc59679
1432d43d7da289
1517833584eece
hexbd34abe71e1

13002119999969 has 2 divisors, whose sum is σ = 13002119999970. Its totient is φ = 13002119999968.

The previous prime is 13002119999941. The next prime is 13002120000031. The reversal of 13002119999969 is 96999991120031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10983126246400 + 2018993753569 = 3314080^2 + 1420913^2 .

It is a cyclic number.

It is not a de Polignac number, because 13002119999969 - 212 = 13002119995873 is a prime.

It is a super-2 number, since 2×130021199999692 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13002119999899 and 13002119999908.

It is not a weakly prime, because it can be changed into another prime (13002119999909) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6501059999984 + 6501059999985.

It is an arithmetic number, because the mean of its divisors is an integer number (6501059999985).

Almost surely, 213002119999969 is an apocalyptic number.

It is an amenable number.

13002119999969 is a deficient number, since it is larger than the sum of its proper divisors (1).

13002119999969 is an equidigital number, since it uses as much as digits as its factorization.

13002119999969 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 19131876, while the sum is 68.

The spelling of 13002119999969 in words is "thirteen trillion, two billion, one hundred nineteen million, nine hundred ninety-nine thousand, nine hundred sixty-nine".