Base | Representation |
---|---|
bin | 1011110100110100101011… |
… | …0000011001000010011010 |
3 | 1201000222202010001001222221 |
4 | 2331031022300121002122 |
5 | 3201011320233020232 |
6 | 43353031435534254 |
7 | 2511241442135425 |
oct | 275151260310232 |
9 | 51028663031887 |
10 | 13002120204442 |
11 | 4163193988776 |
12 | 155ba938ba38a |
13 | 73412cccb765 |
14 | 32d43d8509bc |
15 | 178335890897 |
hex | bd34ac1909a |
13002120204442 has 8 divisors (see below), whose sum is σ = 19534687869600. Its totient is φ = 6490557581244.
The previous prime is 13002120204433. The next prime is 13002120204457. The reversal of 13002120204442 is 24440202120031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5251258942 + ... + 5251261417.
It is an arithmetic number, because the mean of its divisors is an integer number (2441835983700).
Almost surely, 213002120204442 is an apocalyptic number.
13002120204442 is a deficient number, since it is larger than the sum of its proper divisors (6532567665158).
13002120204442 is a wasteful number, since it uses less digits than its factorization.
13002120204442 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10502520980.
The product of its (nonzero) digits is 3072, while the sum is 25.
Adding to 13002120204442 its reverse (24440202120031), we get a palindrome (37442322324473).
The spelling of 13002120204442 in words is "thirteen trillion, two billion, one hundred twenty million, two hundred four thousand, four hundred forty-two".
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