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130021443141 = 343340481047
BaseRepresentation
bin111100100010111100…
…0011100011001000101
3110102121102021200002020
41321011320130121011
54112240442140031
6135421522433353
712252024013542
oct1710570343105
9412542250066
10130021443141
1150161795737
1221247b02859
13c351471a95
14641628bbc9
1535aeb9c096
hex1e45e1c645

130021443141 has 4 divisors (see below), whose sum is σ = 173361924192. Its totient is φ = 86680962092.

The previous prime is 130021443119. The next prime is 130021443161. The reversal of 130021443141 is 141344120031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 130021443141 - 229 = 129484572229 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130021443161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21670240521 + ... + 21670240526.

It is an arithmetic number, because the mean of its divisors is an integer number (43340481048).

Almost surely, 2130021443141 is an apocalyptic number.

It is an amenable number.

130021443141 is a deficient number, since it is larger than the sum of its proper divisors (43340481051).

130021443141 is an equidigital number, since it uses as much as digits as its factorization.

130021443141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 43340481050.

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 130021443141 its reverse (141344120031), we get a palindrome (271365563172).

The spelling of 130021443141 in words is "one hundred thirty billion, twenty-one million, four hundred forty-three thousand, one hundred forty-one".

Divisors: 1 3 43340481047 130021443141