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13002201112093 = 43929617770187
BaseRepresentation
bin1011110100110100111110…
…0101000001111000011101
31201000222221202021121102121
42331031033211001320131
53201012001441041333
643353043450022541
72511243443631664
oct275151745017035
951028852247377
1013002201112093
1141632256198a6
12155bab6a17a51
137341439b8ccb
1432d44a4b1ddb
1517833ca2332d
hexbd34f941e1d

13002201112093 has 4 divisors (see below), whose sum is σ = 13031818882720. Its totient is φ = 12972583341468.

The previous prime is 13002201112081. The next prime is 13002201112133. The reversal of 13002201112093 is 39021110220031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13002201112093 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13002201112393) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14808884655 + ... + 14808885532.

It is an arithmetic number, because the mean of its divisors is an integer number (3257954720680).

Almost surely, 213002201112093 is an apocalyptic number.

It is an amenable number.

13002201112093 is a deficient number, since it is larger than the sum of its proper divisors (29617770627).

13002201112093 is an equidigital number, since it uses as much as digits as its factorization.

13002201112093 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 29617770626.

The product of its (nonzero) digits is 648, while the sum is 25.

The spelling of 13002201112093 in words is "thirteen trillion, two billion, two hundred one million, one hundred twelve thousand, ninety-three".

Divisors: 1 439 29617770187 13002201112093