13002241341431 has 4 divisors (see below), whose sum is σ = 13002419481000. Its totient is φ = 13002063201864.

The previous prime is 13002241341421. The next prime is 13002241341517. The reversal of 13002241341431 is 13414314220031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13002241341431 - 2²² = 13002237147127 is a prime.

It is a super-2 number, since 2×13002241341431² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13002241341394 and 13002241341403.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13002241341421) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 88960256 + ... + 89106293.

It is an arithmetic number, because the mean of its divisors is an integer number (3250604870250).

Almost surely, 2^{13002241341431} is an apocalyptic number.

13002241341431 is a deficient number, since it is larger than the sum of its proper divisors (178139569).

13002241341431 is an equidigital number, since it uses as much as digits as its factorization.

13002241341431 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 178139568.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 13002241341431 its reverse (13414314220031), we get a palindrome (26416555561462).

The spelling of 13002241341431 in words is "thirteen trillion, two billion, two hundred forty-one million, three hundred forty-one thousand, four hundred thirty-one".