Base | Representation |
---|---|
bin | 11101100100000101010110… |
… | …110010110001001110111001 |
3 | 122001101002002111122021222101 |
4 | 131210011112302301032321 |
5 | 114020244101240214431 |
6 | 1140311424143223401 |
7 | 36246565114635613 |
oct | 3544052662611671 |
9 | 561332074567871 |
10 | 130023001101241 |
11 | 3847a49947a006 |
12 | 126bb3b3ba7b61 |
13 | 577216893b671 |
14 | 241720ac95db3 |
15 | 10072e3a24961 |
hex | 764156cb13b9 |
130023001101241 has 2 divisors, whose sum is σ = 130023001101242. Its totient is φ = 130023001101240.
The previous prime is 130023001101101. The next prime is 130023001101283. The reversal of 130023001101241 is 142101100320031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 70940780343225 + 59082220758016 = 8422635^2 + 7686496^2 .
It is a cyclic number.
It is not a de Polignac number, because 130023001101241 - 217 = 130023000970169 is a prime.
It is not a weakly prime, because it can be changed into another prime (130023011101241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65011500550620 + 65011500550621.
It is an arithmetic number, because the mean of its divisors is an integer number (65011500550621).
Almost surely, 2130023001101241 is an apocalyptic number.
It is an amenable number.
130023001101241 is a deficient number, since it is larger than the sum of its proper divisors (1).
130023001101241 is an equidigital number, since it uses as much as digits as its factorization.
130023001101241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 130023001101241 its reverse (142101100320031), we get a palindrome (272124101421272).
The spelling of 130023001101241 in words is "one hundred thirty trillion, twenty-three billion, one million, one hundred one thousand, two hundred forty-one".
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