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130023001101241 is a prime number
BaseRepresentation
bin11101100100000101010110…
…110010110001001110111001
3122001101002002111122021222101
4131210011112302301032321
5114020244101240214431
61140311424143223401
736246565114635613
oct3544052662611671
9561332074567871
10130023001101241
113847a49947a006
12126bb3b3ba7b61
13577216893b671
14241720ac95db3
1510072e3a24961
hex764156cb13b9

130023001101241 has 2 divisors, whose sum is σ = 130023001101242. Its totient is φ = 130023001101240.

The previous prime is 130023001101101. The next prime is 130023001101283. The reversal of 130023001101241 is 142101100320031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 70940780343225 + 59082220758016 = 8422635^2 + 7686496^2 .

It is a cyclic number.

It is not a de Polignac number, because 130023001101241 - 217 = 130023000970169 is a prime.

It is not a weakly prime, because it can be changed into another prime (130023011101241) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65011500550620 + 65011500550621.

It is an arithmetic number, because the mean of its divisors is an integer number (65011500550621).

Almost surely, 2130023001101241 is an apocalyptic number.

It is an amenable number.

130023001101241 is a deficient number, since it is larger than the sum of its proper divisors (1).

130023001101241 is an equidigital number, since it uses as much as digits as its factorization.

130023001101241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 130023001101241 its reverse (142101100320031), we get a palindrome (272124101421272).

The spelling of 130023001101241 in words is "one hundred thirty trillion, twenty-three billion, one million, one hundred one thousand, two hundred forty-one".