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13002300110355 = 359411741952883
BaseRepresentation
bin1011110100110101010101…
…1110101011011000010011
31201001000012122120020111220
42331031111132223120103
53201012202312012410
643353101343540123
72511246055252443
oct275152536533023
951030178506456
1013002300110355
114163276496746
12155bb23bba643
1373415b36b86a
1432d4596c2123
1517834657b070
hexbd3557ab613

13002300110355 has 32 divisors (see below), whose sum is σ = 20827377642240. Its totient is φ = 6926662043520.

The previous prime is 13002300110309. The next prime is 13002300110399. The reversal of 13002300110355 is 55301100320031.

It is not a de Polignac number, because 13002300110355 - 212 = 13002300106259 is a prime.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 245842744 + ... + 245895626.

It is an arithmetic number, because the mean of its divisors is an integer number (650855551320).

Almost surely, 213002300110355 is an apocalyptic number.

13002300110355 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

13002300110355 is a deficient number, since it is larger than the sum of its proper divisors (7825077531885).

13002300110355 is a wasteful number, since it uses less digits than its factorization.

13002300110355 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 71251.

The product of its (nonzero) digits is 1350, while the sum is 24.

Adding to 13002300110355 its reverse (55301100320031), we get a palindrome (68303400430386).

The spelling of 13002300110355 in words is "thirteen trillion, two billion, three hundred million, one hundred ten thousand, three hundred fifty-five".

Divisors: 1 3 5 15 941 2823 4705 14115 17419 52257 52883 87095 158649 261285 264415 793245 16391279 49173837 49762903 81956395 149288709 245869185 248814515 746443545 921168977 2763506931 4605844885 13817534655 866820007357 2600460022071 4334100036785 13002300110355