Base | Representation |
---|---|
bin | 1011110100110101010101… |
… | …1110101011011000010011 |
3 | 1201001000012122120020111220 |
4 | 2331031111132223120103 |
5 | 3201012202312012410 |
6 | 43353101343540123 |
7 | 2511246055252443 |
oct | 275152536533023 |
9 | 51030178506456 |
10 | 13002300110355 |
11 | 4163276496746 |
12 | 155bb23bba643 |
13 | 73415b36b86a |
14 | 32d4596c2123 |
15 | 17834657b070 |
hex | bd3557ab613 |
13002300110355 has 32 divisors (see below), whose sum is σ = 20827377642240. Its totient is φ = 6926662043520.
The previous prime is 13002300110309. The next prime is 13002300110399. The reversal of 13002300110355 is 55301100320031.
It is not a de Polignac number, because 13002300110355 - 212 = 13002300106259 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 245842744 + ... + 245895626.
It is an arithmetic number, because the mean of its divisors is an integer number (650855551320).
Almost surely, 213002300110355 is an apocalyptic number.
13002300110355 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13002300110355 is a deficient number, since it is larger than the sum of its proper divisors (7825077531885).
13002300110355 is a wasteful number, since it uses less digits than its factorization.
13002300110355 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 71251.
The product of its (nonzero) digits is 1350, while the sum is 24.
Adding to 13002300110355 its reverse (55301100320031), we get a palindrome (68303400430386).
The spelling of 13002300110355 in words is "thirteen trillion, two billion, three hundred million, one hundred ten thousand, three hundred fifty-five".
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