Base | Representation |
---|---|
bin | 1011110100110101011011… |
… | …1011000000001110110011 |
3 | 1201001000021100002212022120 |
4 | 2331031112323000032303 |
5 | 3201012230011004021 |
6 | 43353104010405323 |
7 | 2511246501054225 |
oct | 275152673001663 |
9 | 51030240085276 |
10 | 13002324313011 |
11 | 4163289117540 |
12 | 155bb30130843 |
13 | 734163393b67 |
14 | 32d45c9c2415 |
15 | 17834875c2c6 |
hex | bd356ec03b3 |
13002324313011 has 32 divisors (see below), whose sum is σ = 19197363102720. Its totient is φ = 7761965702400.
The previous prime is 13002324313007. The next prime is 13002324313031. The reversal of 13002324313011 is 11031342320031.
It is not a de Polignac number, because 13002324313011 - 22 = 13002324313007 is a prime.
It is a super-2 number, since 2×130023243130112 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (13002324313031) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4825810 + ... + 7020903.
It is an arithmetic number, because the mean of its divisors is an integer number (599917596960).
Almost surely, 213002324313011 is an apocalyptic number.
13002324313011 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
13002324313011 is a deficient number, since it is larger than the sum of its proper divisors (6195038789709).
13002324313011 is a wasteful number, since it uses less digits than its factorization.
13002324313011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11847227.
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 13002324313011 its reverse (11031342320031), we get a palindrome (24033666633042).
The spelling of 13002324313011 in words is "thirteen trillion, two billion, three hundred twenty-four million, three hundred thirteen thousand, eleven".
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