Base | Representation |
---|---|
bin | 10010111010111011111… |
… | …100100001110111010011 |
3 | 11121022010111101211222212 |
4 | 102322323330201313103 |
5 | 132300334213031011 |
6 | 2433152520422335 |
7 | 162636664644221 |
oct | 22727374416723 |
9 | 4538114354885 |
10 | 1300233330131 |
11 | 4614758aa60a |
12 | 18bbb16179ab |
13 | 957c45513c8 |
14 | 46d08565b11 |
15 | 23c4e66508b |
hex | 12ebbf21dd3 |
1300233330131 has 2 divisors, whose sum is σ = 1300233330132. Its totient is φ = 1300233330130.
The previous prime is 1300233330107. The next prime is 1300233330139. The reversal of 1300233330131 is 1310333320031.
It is a strong prime.
It is an emirp because it is prime and its reverse (1310333320031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1300233330131 - 234 = 1283053460947 is a prime.
It is a super-2 number, since 2×13002333301312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1300233330097 and 1300233330106.
It is not a weakly prime, because it can be changed into another prime (1300233330139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650116665065 + 650116665066.
It is an arithmetic number, because the mean of its divisors is an integer number (650116665066).
Almost surely, 21300233330131 is an apocalyptic number.
1300233330131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1300233330131 is an equidigital number, since it uses as much as digits as its factorization.
1300233330131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1458, while the sum is 23.
Adding to 1300233330131 its reverse (1310333320031), we get a palindrome (2610566650162).
The spelling of 1300233330131 in words is "one trillion, three hundred billion, two hundred thirty-three million, three hundred thirty thousand, one hundred thirty-one".
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