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130025412212663 = 1111820492019333
BaseRepresentation
bin11101100100000111100110…
…100000011011011110110111
3122001101022022112120110001102
4131210013212200123132313
5114020314021011301123
61140312503313520315
736250011633021152
oct3544074640333667
9561338275513042
10130025412212663
1138480516490780
12126bb96757309b
135772461317a06
1424173991a8c99
1510073d5543028
hex7641e681b7b7

130025412212663 has 4 divisors (see below), whose sum is σ = 141845904232008. Its totient is φ = 118204920193320.

The previous prime is 130025412212659. The next prime is 130025412212713. The reversal of 130025412212663 is 366212214520031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130025412212663 - 22 = 130025412212659 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130025412212653) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5910246009656 + ... + 5910246009677.

It is an arithmetic number, because the mean of its divisors is an integer number (35461476058002).

Almost surely, 2130025412212663 is an apocalyptic number.

130025412212663 is a deficient number, since it is larger than the sum of its proper divisors (11820492019345).

130025412212663 is a wasteful number, since it uses less digits than its factorization.

130025412212663 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11820492019344.

The product of its (nonzero) digits is 103680, while the sum is 38.

Adding to 130025412212663 its reverse (366212214520031), we get a palindrome (496237626732694).

The spelling of 130025412212663 in words is "one hundred thirty trillion, twenty-five billion, four hundred twelve million, two hundred twelve thousand, six hundred sixty-three".

Divisors: 1 11 11820492019333 130025412212663