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13002550522457 is a prime number
BaseRepresentation
bin1011110100110110010001…
…1001111011001001011001
31201001000212002202111100012
42331031210121323021121
53201013210413204312
643353142251051305
72511255215602046
oct275154431731131
951030762674305
1013002550522457
114163394880aa1
12155bb93a40b35
1373419b1c69c2
1432d480a681cd
1517835d542322
hexbd36467b259

13002550522457 has 2 divisors, whose sum is σ = 13002550522458. Its totient is φ = 13002550522456.

The previous prime is 13002550522397. The next prime is 13002550522571. The reversal of 13002550522457 is 75422505520031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8703774446656 + 4298776075801 = 2950216^2 + 2073349^2 .

It is a cyclic number.

It is not a de Polignac number, because 13002550522457 - 226 = 13002483413593 is a prime.

It is a super-2 number, since 2×130025505224572 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13002550525457) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6501275261228 + 6501275261229.

It is an arithmetic number, because the mean of its divisors is an integer number (6501275261229).

Almost surely, 213002550522457 is an apocalyptic number.

It is an amenable number.

13002550522457 is a deficient number, since it is larger than the sum of its proper divisors (1).

13002550522457 is an equidigital number, since it uses as much as digits as its factorization.

13002550522457 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 420000, while the sum is 41.

The spelling of 13002550522457 in words is "thirteen trillion, two billion, five hundred fifty million, five hundred twenty-two thousand, four hundred fifty-seven".