Base | Representation |
---|---|
bin | 1011110100110110010010… |
… | …0000111010000100010010 |
3 | 1201001000212020012111102122 |
4 | 2331031210200322010102 |
5 | 3201013211400244132 |
6 | 43353142354214242 |
7 | 2511255240265040 |
oct | 275154440720422 |
9 | 51030766174378 |
10 | 13002552353042 |
11 | 416339591137a |
12 | 155bb94584382 |
13 | 73419b6b7ca5 |
14 | 32d480dc3390 |
15 | 17835d7a4912 |
hex | bd36483a112 |
13002552353042 has 64 divisors (see below), whose sum is σ = 22960755175680. Its totient is φ = 5405769363456.
The previous prime is 13002552353041. The next prime is 13002552353059. The reversal of 13002552353042 is 24035325520031.
It is a junction number, because it is equal to n+sod(n) for n = 13002552352993 and 13002552353011.
It is not an unprimeable number, because it can be changed into a prime (13002552353041) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 385666778 + ... + 385700490.
It is an arithmetic number, because the mean of its divisors is an integer number (358761799620).
Almost surely, 213002552353042 is an apocalyptic number.
13002552353042 is a deficient number, since it is larger than the sum of its proper divisors (9958202822638).
13002552353042 is a wasteful number, since it uses less digits than its factorization.
13002552353042 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 35955.
The product of its (nonzero) digits is 108000, while the sum is 35.
Adding to 13002552353042 its reverse (24035325520031), we get a palindrome (37037877873073).
The spelling of 13002552353042 in words is "thirteen trillion, two billion, five hundred fifty-two million, three hundred fifty-three thousand, forty-two".
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