Base | Representation |
---|---|
bin | 111100100011001100… |
… | …1000110001110011111 |
3 | 110102122000101120010212 |
4 | 1321012121012032133 |
5 | 4112300140044403 |
6 | 135422430123035 |
7 | 12252156534650 |
oct | 1710631061637 |
9 | 412560346125 |
10 | 130030003103 |
11 | 50166601990 |
12 | 2124a95047b |
13 | c35317b050 |
14 | 6417479527 |
15 | 35b07dd4d8 |
hex | 1e4664639f |
130030003103 has 32 divisors (see below), whose sum is σ = 174851550720. Its totient is φ = 93385676160.
The previous prime is 130030003097. The next prime is 130030003109. The reversal of 130030003103 is 301300030031.
It is an interprime number because it is at equal distance from previous prime (130030003097) and next prime (130030003109).
It is a de Polignac number, because none of the positive numbers 2k-130030003103 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130030003109) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 561101 + ... + 758217.
It is an arithmetic number, because the mean of its divisors is an integer number (5464110960).
Almost surely, 2130030003103 is an apocalyptic number.
130030003103 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
130030003103 is a deficient number, since it is larger than the sum of its proper divisors (44821547617).
130030003103 is a wasteful number, since it uses less digits than its factorization.
130030003103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 197807.
The product of its (nonzero) digits is 81, while the sum is 14.
Adding to 130030003103 its reverse (301300030031), we get a palindrome (431330033134).
The spelling of 130030003103 in words is "one hundred thirty billion, thirty million, three thousand, one hundred three".
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