Base | Representation |
---|---|
bin | 1011110100110111111111… |
… | …0010110001001010000011 |
3 | 1201001002001010101101102122 |
4 | 2331031333302301022003 |
5 | 3201020131031114341 |
6 | 43353300023434455 |
7 | 2511302465345666 |
oct | 275157762611203 |
9 | 51032033341378 |
10 | 13003010019971 |
11 | 4163600194304 |
12 | 15600a18b5a2b |
13 | 73424246a61a |
14 | 32d4c5ab96dd |
15 | 178388a5994b |
hex | bd37fcb1283 |
13003010019971 has 2 divisors, whose sum is σ = 13003010019972. Its totient is φ = 13003010019970.
The previous prime is 13003010019959. The next prime is 13003010020211. The reversal of 13003010019971 is 17991001030031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13003010019971 - 214 = 13003010003587 is a prime.
It is not a weakly prime, because it can be changed into another prime (13003010019371) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6501505009985 + 6501505009986.
It is an arithmetic number, because the mean of its divisors is an integer number (6501505009986).
Almost surely, 213003010019971 is an apocalyptic number.
13003010019971 is a deficient number, since it is larger than the sum of its proper divisors (1).
13003010019971 is an equidigital number, since it uses as much as digits as its factorization.
13003010019971 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5103, while the sum is 35.
The spelling of 13003010019971 in words is "thirteen trillion, three billion, ten million, nineteen thousand, nine hundred seventy-one".
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