Base | Representation |
---|---|
bin | 11101100100001100011000… |
… | …010110100100000001101011 |
3 | 122001101210120010220112022112 |
4 | 131210030120112210001223 |
5 | 114020410023111014230 |
6 | 1140315112414112535 |
7 | 36250253040610310 |
oct | 3544143026440153 |
9 | 561353503815275 |
10 | 130030543454315 |
11 | 38482709988559 |
12 | 12700959aab74b |
13 | 5772a9b40828a |
14 | 2417724870d07 |
15 | 10075d5c70d95 |
hex | 7643185a406b |
130030543454315 has 32 divisors (see below), whose sum is σ = 187759289088000. Its totient is φ = 84450259075968.
The previous prime is 130030543454309. The next prime is 130030543454359. The reversal of 130030543454315 is 513454345030031.
It is a cyclic number.
It is not a de Polignac number, because 130030543454315 - 228 = 130030275018859 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 21255920 + ... + 26680989.
It is an arithmetic number, because the mean of its divisors is an integer number (5867477784000).
Almost surely, 2130030543454315 is an apocalyptic number.
130030543454315 is a deficient number, since it is larger than the sum of its proper divisors (57728745633685).
130030543454315 is a wasteful number, since it uses less digits than its factorization.
130030543454315 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 47941019.
The product of its (nonzero) digits is 648000, while the sum is 41.
Adding to 130030543454315 its reverse (513454345030031), we get a palindrome (643484888484346).
The spelling of 130030543454315 in words is "one hundred thirty trillion, thirty billion, five hundred forty-three million, four hundred fifty-four thousand, three hundred fifteen".
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