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130030543454531 is a prime number
BaseRepresentation
bin11101100100001100011000…
…010110100100000101000011
3122001101210120010220112121112
4131210030120112210011003
5114020410023111021111
61140315112414113535
736250253040611036
oct3544143026440503
9561353503815545
10130030543454531
1138482709988735
1212700959aab8ab
135772a9b4083c5
14241772487101d
1510075d5c70e8b
hex7643185a4143

130030543454531 has 2 divisors, whose sum is σ = 130030543454532. Its totient is φ = 130030543454530.

The previous prime is 130030543454393. The next prime is 130030543454551. The reversal of 130030543454531 is 135454345030031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 130030543454531 - 226 = 130030476345667 is a prime.

It is a super-2 number, since 2×1300305434545312 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (130030543454551) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65015271727265 + 65015271727266.

It is an arithmetic number, because the mean of its divisors is an integer number (65015271727266).

Almost surely, 2130030543454531 is an apocalyptic number.

130030543454531 is a deficient number, since it is larger than the sum of its proper divisors (1).

130030543454531 is an equidigital number, since it uses as much as digits as its factorization.

130030543454531 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648000, while the sum is 41.

Adding to 130030543454531 its reverse (135454345030031), we get a palindrome (265484888484562).

The spelling of 130030543454531 in words is "one hundred thirty trillion, thirty billion, five hundred forty-three million, four hundred fifty-four thousand, five hundred thirty-one".