Base | Representation |
---|---|
bin | 11101100100001101000001… |
… | …011001111011100101110001 |
3 | 122001101212100010220121001120 |
4 | 131210031001121323211301 |
5 | 114020412430420444441 |
6 | 1140315305020252453 |
7 | 36250306103101314 |
oct | 3544150131734561 |
9 | 561355303817046 |
10 | 130031232203121 |
11 | 38482a32742747 |
12 | 12700b106a1129 |
13 | 5772b7b008452 |
14 | 241778c11a97b |
15 | 100762646e966 |
hex | 76434167b971 |
130031232203121 has 16 divisors (see below), whose sum is σ = 174037892595840. Its totient is φ = 86356098120960.
The previous prime is 130031232203113. The next prime is 130031232203123. The reversal of 130031232203121 is 121302232130031.
It is not a de Polignac number, because 130031232203121 - 23 = 130031232203113 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 130031232203091 and 130031232203100.
It is not an unprimeable number, because it can be changed into a prime (130031232203123) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 877000 + ... + 16150281.
It is an arithmetic number, because the mean of its divisors is an integer number (10877368287240).
Almost surely, 2130031232203121 is an apocalyptic number.
It is an amenable number.
130031232203121 is a deficient number, since it is larger than the sum of its proper divisors (44006660392719).
130031232203121 is a wasteful number, since it uses less digits than its factorization.
130031232203121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17037016.
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 130031232203121 its reverse (121302232130031), we get a palindrome (251333464333152).
The spelling of 130031232203121 in words is "one hundred thirty trillion, thirty-one billion, two hundred thirty-two million, two hundred three thousand, one hundred twenty-one".
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