Search a number
-
+
13003205245 = 52626399023
BaseRepresentation
bin11000001110000110…
…10010101001111101
31020120012211021020021
430013003102221331
5203112310031440
65550143452141
7640142264242
oct140703225175
936505737207
1013003205245
115572a74618
12262a8b7051
1312c2c548b4
148b4d615c9
1551188684a
hex3070d2a7d

13003205245 has 8 divisors (see below), whose sum is σ = 15604598016. Its totient is φ = 10402063056.

The previous prime is 13003205213. The next prime is 13003205263. The reversal of 13003205245 is 54250230031.

13003205245 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13003205245 - 25 = 13003205213 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 81804 + ... + 180826.

It is an arithmetic number, because the mean of its divisors is an integer number (1950574752).

Almost surely, 213003205245 is an apocalyptic number.

It is an amenable number.

13003205245 is a deficient number, since it is larger than the sum of its proper divisors (2601392771).

13003205245 is an equidigital number, since it uses as much as digits as its factorization.

13003205245 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 125291.

The product of its (nonzero) digits is 3600, while the sum is 25.

Adding to 13003205245 its reverse (54250230031), we get a palindrome (67253435276).

The spelling of 13003205245 in words is "thirteen billion, three million, two hundred five thousand, two hundred forty-five".

Divisors: 1 5 26263 99023 131315 495115 2600641049 13003205245