13003210320133 has 4 divisors (see below), whose sum is σ = 14185320349248. Its totient is φ = 11821100291020.

The previous prime is 13003210320091. The next prime is 13003210320167. The reversal of 13003210320133 is 33102301230031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13003210320133 is a prime.

It is a super-2 number, since 2×13003210320133² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13003210320193) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 591055014541 + ... + 591055014562.

It is an arithmetic number, because the mean of its divisors is an integer number (3546330087312).

Almost surely, 2^{13003210320133} is an apocalyptic number.

It is an amenable number.

13003210320133 is a deficient number, since it is larger than the sum of its proper divisors (1182110029115).

13003210320133 is a wasteful number, since it uses less digits than its factorization.

13003210320133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1182110029114.

The product of its (nonzero) digits is 972, while the sum is 22.

Adding to 13003210320133 its reverse (33102301230031), we get a palindrome (46105511550164).

The spelling of 13003210320133 in words is "thirteen trillion, three billion, two hundred ten million, three hundred twenty thousand, one hundred thirty-three".