Base | Representation |
---|---|
bin | 1011110100111000110001… |
… | …1011111111111111110111 |
3 | 1201001002120220112222100000 |
4 | 2331032030123333333313 |
5 | 3201021044332432010 |
6 | 43353333042322343 |
7 | 2511310652435133 |
oct | 275161433777767 |
9 | 51032526488300 |
10 | 13003222155255 |
11 | 41636a9a05722 |
12 | 15601409593b3 |
13 | 7342773b3367 |
14 | 32d505d3a3c3 |
15 | 17839c4ae7c0 |
hex | bd38c6ffff7 |
13003222155255 has 24 divisors (see below), whose sum is σ = 23373693160272. Its totient is φ = 6935051815488.
The previous prime is 13003222155239. The next prime is 13003222155263. The reversal of 13003222155255 is 55255122230031.
13003222155255 is a `hidden beast` number, since 1 + 3 + 0 + 0 + 32 + 2 + 21 + 552 + 55 = 666.
It is not a de Polignac number, because 13003222155255 - 24 = 13003222155239 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 5351119014 + ... + 5351121443.
It is an arithmetic number, because the mean of its divisors is an integer number (973903881678).
Almost surely, 213003222155255 is an apocalyptic number.
13003222155255 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13003222155255 is a deficient number, since it is larger than the sum of its proper divisors (10370471005017).
13003222155255 is an equidigital number, since it uses as much as digits as its factorization.
13003222155255 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10702240477 (or 10702240465 counting only the distinct ones).
The product of its (nonzero) digits is 90000, while the sum is 36.
Adding to 13003222155255 its reverse (55255122230031), we get a palindrome (68258344385286).
The spelling of 13003222155255 in words is "thirteen trillion, three billion, two hundred twenty-two million, one hundred fifty-five thousand, two hundred fifty-five".
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