Base | Representation |
---|---|
bin | 1011110100111000110110… |
… | …1001101110100101000101 |
3 | 1201001002122022220011210110 |
4 | 2331032031221232211011 |
5 | 3201021120041444031 |
6 | 43353335051143233 |
7 | 2511311320561062 |
oct | 275161551564505 |
9 | 51032568804713 |
10 | 13003242531141 |
11 | 416370a4623a5 |
12 | 1560147744b19 |
13 | 73427b6988b5 |
14 | 32d508921c69 |
15 | 17839e186c46 |
hex | bd38da6e945 |
13003242531141 has 16 divisors (see below), whose sum is σ = 17351717087744. Its totient is φ = 8661800602224.
The previous prime is 13003242531133. The next prime is 13003242531157. The reversal of 13003242531141 is 14113524230031.
It is not a de Polignac number, because 13003242531141 - 23 = 13003242531133 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13003242531099 and 13003242531108.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13003242531101) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 21238590 + ... + 21842256.
It is an arithmetic number, because the mean of its divisors is an integer number (1084482317984).
Almost surely, 213003242531141 is an apocalyptic number.
It is an amenable number.
13003242531141 is a deficient number, since it is larger than the sum of its proper divisors (4348474556603).
13003242531141 is a wasteful number, since it uses less digits than its factorization.
13003242531141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 609480.
The product of its (nonzero) digits is 8640, while the sum is 30.
Adding to 13003242531141 its reverse (14113524230031), we get a palindrome (27116766761172).
The spelling of 13003242531141 in words is "thirteen trillion, three billion, two hundred forty-two million, five hundred thirty-one thousand, one hundred forty-one".
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