Base | Representation |
---|---|
bin | 111100100011010001… |
… | …0110100011000010101 |
3 | 110102122012012000210220 |
4 | 1321012202310120111 |
5 | 4112301313121240 |
6 | 135423000504553 |
7 | 12252220310346 |
oct | 1710642643025 |
9 | 412565160726 |
10 | 130032551445 |
11 | 50167a92555 |
12 | 2124b77b159 |
13 | c353860c44 |
14 | 64179400cd |
15 | 35b0b435d0 |
hex | 1e468b4615 |
130032551445 has 32 divisors (see below), whose sum is σ = 213271349760. Its totient is φ = 67613237760.
The previous prime is 130032551437. The next prime is 130032551459. The reversal of 130032551445 is 544155230031.
It is not a de Polignac number, because 130032551445 - 23 = 130032551437 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 843411 + ... + 985599.
It is an arithmetic number, because the mean of its divisors is an integer number (6664729680).
Almost surely, 2130032551445 is an apocalyptic number.
130032551445 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
130032551445 is a deficient number, since it is larger than the sum of its proper divisors (83238798315).
130032551445 is a wasteful number, since it uses less digits than its factorization.
130032551445 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 143725.
The product of its (nonzero) digits is 36000, while the sum is 33.
Adding to 130032551445 its reverse (544155230031), we get a palindrome (674187781476).
The spelling of 130032551445 in words is "one hundred thirty billion, thirty-two million, five hundred fifty-one thousand, four hundred forty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.066 sec. • engine limits •