Base | Representation |
---|---|
bin | 11101100100001110010000… |
… | …000110000110100000111110 |
3 | 122001101222202011002210122110 |
4 | 131210032100012012200332 |
5 | 114020423131403430204 |
6 | 1140320044020554450 |
7 | 36250353603451455 |
oct | 3544162006064076 |
9 | 561358664083573 |
10 | 130032552405054 |
11 | 3848354a988a22 |
12 | 1270121a852a26 |
13 | 577302b697720 |
14 | 24178755b9b9c |
15 | 10076a2300889 |
hex | 76439018683e |
130032552405054 has 16 divisors (see below), whose sum is σ = 280070112872592. Its totient is φ = 40010016124608.
The previous prime is 130032552405043. The next prime is 130032552405059. The reversal of 130032552405054 is 450504255230031.
It is a super-2 number, since 2×1300325524050542 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (39).
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130032552405059) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 833542002519 + ... + 833542002674.
It is an arithmetic number, because the mean of its divisors is an integer number (17504382054537).
Almost surely, 2130032552405054 is an apocalyptic number.
130032552405054 is an abundant number, since it is smaller than the sum of its proper divisors (150037560467538).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130032552405054 is a wasteful number, since it uses less digits than its factorization.
130032552405054 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1667084005211.
The product of its (nonzero) digits is 360000, while the sum is 39.
The spelling of 130032552405054 in words is "one hundred thirty trillion, thirty-two billion, five hundred fifty-two million, four hundred five thousand, fifty-four".
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