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130033000057 is a prime number
BaseRepresentation
bin111100100011010010…
…0100001111001111001
3110102122020000211012011
41321012210201321321
54112301422000212
6135423014245521
712252224156302
oct1710644417171
9412566024164
10130033000057
1150168269604
122124b9568a1
13c35398a1ac
146417a197a9
1535b0bd14a7
hex1e46921e79

130033000057 has 2 divisors, whose sum is σ = 130033000058. Its totient is φ = 130033000056.

The previous prime is 130032999991. The next prime is 130033000063. The reversal of 130033000057 is 750000330031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 98257798521 + 31775201536 = 313461^2 + 178256^2 .

It is a cyclic number.

It is not a de Polignac number, because 130033000057 - 223 = 130024611449 is a prime.

It is a super-2 number, since 2×1300330000572 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (130033000087) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65016500028 + 65016500029.

It is an arithmetic number, because the mean of its divisors is an integer number (65016500029).

Almost surely, 2130033000057 is an apocalyptic number.

It is an amenable number.

130033000057 is a deficient number, since it is larger than the sum of its proper divisors (1).

130033000057 is an equidigital number, since it uses as much as digits as its factorization.

130033000057 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 945, while the sum is 22.

Adding to 130033000057 its reverse (750000330031), we get a palindrome (880033330088).

The spelling of 130033000057 in words is "one hundred thirty billion, thirty-three million, fifty-seven", and thus it is an aban number.