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1300331210020 = 22565016560501
BaseRepresentation
bin10010111011000001110…
…001111010010100100100
311121022101022120122221221
4102323001301322110210
5132301034242210040
62433210334350124
7162642263626303
oct22730161722444
94538338518857
101300331210020
11461516083187
1219001a35b344
139580b901bbb
1446d1756443a
1523c5804b74a
hex12ec1c7a524

1300331210020 has 12 divisors (see below), whose sum is σ = 2730695541084. Its totient is φ = 520132484000.

The previous prime is 1300331209999. The next prime is 1300331210023. The reversal of 1300331210020 is 200121330031.

It can be written as a sum of positive squares in 2 ways, for example, as 575425410624 + 724905799396 = 758568^2 + 851414^2 .

It is a super-2 number, since 2×13003312100202 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1300331209976 and 1300331210003.

It is not an unprimeable number, because it can be changed into a prime (1300331210023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32508280231 + ... + 32508280270.

It is an arithmetic number, because the mean of its divisors is an integer number (227557961757).

Almost surely, 21300331210020 is an apocalyptic number.

1300331210020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1300331210020 is an abundant number, since it is smaller than the sum of its proper divisors (1430364331064).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1300331210020 is a wasteful number, since it uses less digits than its factorization.

1300331210020 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 65016560510 (or 65016560508 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 16.

Adding to 1300331210020 its reverse (200121330031), we get a palindrome (1500452540051).

The spelling of 1300331210020 in words is "one trillion, three hundred billion, three hundred thirty-one million, two hundred ten thousand, twenty".

Divisors: 1 2 4 5 10 20 65016560501 130033121002 260066242004 325082802505 650165605010 1300331210020