Base | Representation |
---|---|
bin | 100110110000001… |
… | …0111111001010001 |
3 | 10100121210201022122 |
4 | 1031200113321101 |
5 | 10130341111423 |
6 | 333010344025 |
7 | 44136432503 |
oct | 11540277121 |
9 | 3317721278 |
10 | 1300332113 |
11 | 608004843 |
12 | 30358b015 |
13 | 1795231b2 |
14 | c49a9d73 |
15 | 792588c8 |
hex | 4d817e51 |
1300332113 has 2 divisors, whose sum is σ = 1300332114. Its totient is φ = 1300332112.
The previous prime is 1300332101. The next prime is 1300332139. The reversal of 1300332113 is 3112330031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 800720209 + 499611904 = 28297^2 + 22352^2 .
It is a cyclic number.
It is not a de Polignac number, because 1300332113 - 222 = 1296137809 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1300332091 and 1300332100.
It is not a weakly prime, because it can be changed into another prime (1300332413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650166056 + 650166057.
It is an arithmetic number, because the mean of its divisors is an integer number (650166057).
Almost surely, 21300332113 is an apocalyptic number.
It is an amenable number.
1300332113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1300332113 is an equidigital number, since it uses as much as digits as its factorization.
1300332113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 162, while the sum is 17.
The square root of 1300332113 is about 36060.1180391856. The cubic root of 1300332113 is about 1091.4858150874.
Adding to 1300332113 its reverse (3112330031), we get a palindrome (4412662144).
The spelling of 1300332113 in words is "one billion, three hundred million, three hundred thirty-two thousand, one hundred thirteen".
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