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13003404000 = 2535310331049
BaseRepresentation
bin11000001110001000…
…00011001011100000
31020120020012100212120
430013010003023200
5203112332412000
65550152024240
7640144052556
oct140704031340
936506170776
1013003404000
11557309a984
12262a992080
1312c2cc41c2
148b4db3bd6
155118c56a0
hex3071032e0

13003404000 has 192 divisors, whose sum is σ = 42681038400. Its totient is φ = 3460915200.

The previous prime is 13003403957. The next prime is 13003404013. The reversal of 13003404000 is 40430031.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 12395476 + ... + 12396524.

It is an arithmetic number, because the mean of its divisors is an integer number (222297075).

Almost surely, 213003404000 is an apocalyptic number.

13003404000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13003404000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (21340519200).

13003404000 is an abundant number, since it is smaller than the sum of its proper divisors (29677634400).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13003404000 is a wasteful number, since it uses less digits than its factorization.

13003404000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2110 (or 2092 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 15.

Adding to 13003404000 its reverse (40430031), we get a palindrome (13043834031).

The spelling of 13003404000 in words is "thirteen billion, three million, four hundred four thousand".