Base | Representation |
---|---|
bin | 1011110100111001011111… |
… | …1001000110111010000001 |
3 | 1201001010002022011201112020 |
4 | 2331032113321012322001 |
5 | 3201021443032210410 |
6 | 43353404105352053 |
7 | 2511315505102215 |
oct | 275162771067201 |
9 | 51033068151466 |
10 | 13003414335105 |
11 | 4163798437247 |
12 | 1560195198629 |
13 | 7342a816004c |
14 | 32d523684945 |
15 | 1783ae2c1a70 |
hex | bd397e46e81 |
13003414335105 has 32 divisors (see below), whose sum is σ = 21545527426560. Its totient is φ = 6692756378880.
The previous prime is 13003414335061. The next prime is 13003414335181. The reversal of 13003414335105 is 50153341430031.
It is not a de Polignac number, because 13003414335105 - 216 = 13003414269569 is a prime.
It is a super-2 number, since 2×130034143351052 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 134021145 + ... + 134118134.
It is an arithmetic number, because the mean of its divisors is an integer number (673297732080).
Almost surely, 213003414335105 is an apocalyptic number.
13003414335105 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
13003414335105 is a deficient number, since it is larger than the sum of its proper divisors (8542113091455).
13003414335105 is a wasteful number, since it uses less digits than its factorization.
13003414335105 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 268139401.
The product of its (nonzero) digits is 32400, while the sum is 33.
Adding to 13003414335105 its reverse (50153341430031), we get a palindrome (63156755765136).
The spelling of 13003414335105 in words is "thirteen trillion, three billion, four hundred fourteen million, three hundred thirty-five thousand, one hundred five".
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